A circle passes through the points (0,0) and (0, 1) and also touches the circie `x^2 +y^2=16` The radius of the circle is

Statement-1: The centre of the circle passing through the points (0, 0), (1, 0) and touching the circle C : x^(2)+y^(2)=9 lies inside the circle. Statement-2: If a circle C_(1) passes through the centre of the circle C_(2) and also touches the circle, the radius of the circle C_(2) is twice the radius of circle C_(1)

The centre of a circle passing through the points (0, 0), (1, 0) and touching the circle x^(2)+y^(2)=9 , is

A circle passes through (0,0) and (1,0) and touches the circle x^(2)+y^(2)=9 then the centre of circle is -

If a circle passes through (0,0),(4,0) and touches the circle x^(2)+y^(2)=36 then the centre of circle

The center(s) of the circle(s) passing through the points (0,0) and (1,0) and touching the circle x^(2)+y^(2)=9 is (are) ( a) ((3)/(2),(1)/(2)) (b) ((1)/(2),(3)/(2))(c)((1)/(2),2(1)/(2)) (d) ((1)/(2),-2(1)/(2))

a circle passing through the point (2,2(sqrt(2)-1)) touches the pair of lines x^(2)-y^(2)-4x+4=0. The centre of the circle is

Centre of a circle passing through point (0,1) and touching the curve y=x^2 at (2,4) is