Suppose `int(1-7cos^2x)/(sin^7xcos^2x)dx=(g(x))/(sin^7x)+c` where C is arbitrary constant of integration.then find value of `g'(0)+g''(pi/4)`

Suppose int(1-7cos^(2)x)/(sin^(7)x cos^(2)x)dx=(g(x))/(sin^(7)x)+c where C is arbitrary constant of ^(7)x integration.then find value of g'(0)+g''((pi)/(4))

int(1-7cos^(2)x)/(sin^(7)xcos^(2)x)dx=(f(x))/((sinx)^(7))+C , then f(x) is equal to

int(5cos^3x+7sin^3x)/(sin^2xcos^2x)dx

int(5cos^3x+7sin^3x)/(3sin^2xcos^2x)dx

What is int ((1)/(cos^(2)x) - (1)/(sin^(x)x))dx equal to ? where c is the constant of integration

int5^(x)((1+sin x*cos x*ln5)/(cos^(2)x))dx= ( where c is the constant of integration)

if int x^(5)e^(-x^(2))dx=g(x)e^(-x^(2))+c where c is a constant of integration then g(-1) is equal to

int(sin2x+2)/(sin2x+cos2x+1)dx=f(x)+C where C is integration constant and f(0)=0, then

If int x^(5)e^(-x^(2))dx = g(x)e^(-x^(2))+C , where C is a constant of integration, then g(-1) is equal to

The integral int((x)/(x sin x+cos x))^(2)dx is equal to (where "C" is a constant of integration