A circuit has a battery voltage of 30 V. A lamp resistance of `6Omega` is connected to the circuit. Calculate the current and power of the circuit.

Explanation

`"Current" I = "Voltage" / "Resistance" = 30 / 6 = 5 A`.
Power P = Voltage `xx` Current `= 30 xx 5 = 150` watts.
The lamp gives out 150 W of power in the form of heat and light.

Or Power `P = I^ 2 R = 5^ 2 xx6 =25 xx 6 = 150` watts

Or Power `P = V^ 2 / R = 30^ 2 / 6 = 900 / 6 = 150` watts.