Consider a parallel circuit which consists of three resistors with resistance `5Omega, 10Omega, 5Omega` respectively with a 15V battery.

Explanation

Thus, the total resistance, `1/ R = 1/ R_1 +1/ R_2 +1/ R_3 =1/ 5 + 1/10 +1/ 5 = 5/10`.
So `R = 2Omega`.
In parallel connection, the total resistance or the equivalent resistance will always be less than the smallest resistor present in the circuit. The value of equivalent resistance will be between the smallest resistance in the circuit and the smallest resistance divided by the number of resistors present in the circuit. In this example, the smallest resistor has `5Omega` resistance and the value for total resistance is `2Omega` which clearly justifies the above mentioned fact.
The voltage across each resistor is 15V. Now to find the current across each branch, the formula is
`I = V / R`.
`I_1 = 15/5 =3A`
`I_2 = 15/10 = 1.5A`
`I_3 = 15/5 = 3A`
Total current `I = 3 + 1.5 + 3 = 7.5A`