In quadrilateral ACBD, AC = AD and AB bisects `angle A` (see Fig. 7.16). Show that `triangle ABC cong triangle ABD`. What can you say about BC and BD?

In quadrilateral ABCD AC = AD and AB bisects angleA (see fig. ) DeltaABC ~= DeltaABD . What is the relation between BC and BD ?

In quadrilateral ABCD AC = AD and AB bisects angleA (see fig. ) DeltaABC ~= DeltaABD . What is the relation between BC and BD ?

ABCD is a quadrilateral in which AD = BC and angle DAB =angle CBA (see Fig. 7.17). Prove that (i) triangle ABD cong triangle BAC (ii) BD = AC (iii) angle ABD = angle BAC .

ABC and DBC are two isosceles triangles on the same base BC (See Fig. ). Show that angleABD = angleACD .

ABC and DBC are two isosceles triangles on the same base BC (See Fig. ). Show that angleABD = angleACD .

Line l is the bisector of an angle angle A and B is any point on l. BP and BQ are perpendiculars from B to the arms of angle A (see Fig. 7.20). Show that: (i) triangle APB cong triangle AQB (ii) BP = BQ or B is equidistant from the arms of angle A .

ABC is an isosceles triangle in which AB = AC. AD bisects exterior angle PAC and CD || AB (see Fig. 8.14). Show that (i) angle DAC = angle BCA and (ii) ABCD is a parallelogram.

AD and BC are equal perpendiculars to a line segment AB (see Fig. 7.18). Show that CD bisects AB.

l and m are two parallel lines intersected by another pair of parallel lines p and q (see Fig. 7.19). Show that triangle ABC cong triangle CDA

In DeltaABC , AD is the perpendicular bisector of BC (See Fig. ). Show that DeltaABC is an isosceles triangle in which AB = AC.