In `DeltaABC`, AD is the perpendicular bisector of BC (See Fig.
). Show that `DeltaABC` is an isosceles triangle in which AB = AC.

In triangleABC , AD is the perpendicular bisector of BC. Show that triangleABC is an isosceles triangle in which AB=AC

In Delta ABC , the bisector AD of angle A is perpendicular to side BC (see Fig. 7.27). Show that AB = AC and Delta ABC is isosceles.

ABC is a triangle in which altitudes BE and CF to sides AC and AB are equal (See Fig. ). Show that AB = AC or DeltaABC is an isosceles triangle.

ABC is a triangle in which altitudes BE and CF to sides AC and AB are equal (See Fig. ). Show that AB = AC or DeltaABC is an isosceles triangle.

AD and BC are equal perpendiculars to a line segment AB (see Fig. 7.18). Show that CD bisects AB.

In a DeltaABC, if median AD is perpendicular to AB, the tan A+2 tan B is equal to

In DeltaABC , AC > AB . The bisector of angleA meets BC at D. Prove that angleADB is an acute angle.

ABCD is a trapezium in which AB||CD and AD = BC (See Fig.) Show that /_A = /_B .

ABCD is a trapezium in which AB||CD and AD = BC (See Fig.) Show that /_A = /_B .

In DeltaABC , AC > AB and bisector of angleA meets BC and D then angleADB is :