The origin is shifted to `(1,2),` the equation `y^2-8x-4y+12=0` changes to `Y^2+4aX=0` then `a=`

Origin is shifted to (1,2) then the equation y^(2)-8x-4y+12-0 changes as y^(2)=4ax .Then a=

By shifting origin to (-1,2) the equation y^(2)+8x-4y+12=0 changes as Y^(2)=4aX then a=

The origin shifted to (-5,3) then the equation y^(2)-12x+6y+69=0 changes as y^(2)=4ax then a

Without change of axes the origin is shifted to (h, k), then from the equation x^(2)+y^(2)-4x+6y-7=0 , then therm containing linear powers are missing, then point (h, k) is

If by shifting the origin to (1,2) the equation of the parabola y^(2)-4y+8x-4=0 becomes y^(2)=4ax, then a equal to

The coordinates of the point where origin is shifted is (-1,2) so that the equation 2x^(2)+y^(2)-4x+4y=0 become?

Find the point to which the origin should be shifted so that the equation y^(2)-6y-4x+13=0 is transformed to the form y^(2)+Ax=0

When the origin is shifted to a suitable point, the equation 2x^(2)+y^(2)-4x+4y=0 transformed as 2x^(^^)2+y^^2-8x+8y+18=0^(@) The point to which origin was shifted is