A body is projected at an angle `theta` so that its range is maximum.If `T` is the time of flight then the value of maximum range is (acceleration due to gravity =`g`)

Acceleration due to gravity is maximum at

A ball is thrown at an angle theta with the horizontal and the range is maximum. The value of tantheta is:-

A body is projected so that it has maximum range R. What is the maximum height reached during the flight ?

when a body is projected at an angle 45^@ , its range is maimum. For maximum range, the value of sin 2 theta should be equal to one.

A body is projected with velocity u so that its horizontal range is twice the maximum height.The range is

A particle is projected at an angle with horizontal. If T is the time of flight and R is a horizontal range, then theta is

A particle is projected with a velocity v so that its range on a horizontal plane is twice the greatest height attained. If g is acceleration due to gravity, then its range is

A particle is projeted with a velocity v, so that its range on a horizontal plane is twice the greatest height attained. If g is acceleration due to gravity, then its range is :