A plane passes through `(2, 3,-1)` and is perpendicular to the line having dr's `(3,-4, 7)`.The perpendicular distance from the origin to this plane is `K /(sqrt(74)` then `K `is equal to

If plane passes through the point (1,1,1) and is perpendicular to the line,(x-1)/(3)=(y-1)/(0)=(z-1)/(4), then its perpendicular distance from the origin is

Equation of a plane passing through a point and perpendicular to the line

Equation of the plane passing through (2,-3,4) and perpendicular to Z -axis is

If the perpendicular distance from (1,2,4) to the plane 2x+2y-z+k=0 is 3 then K-4

Find the equation of the plane passing through the point (1,2,1) and perpendicular to the line joining the points (1,4,2) and (2,3,5) . find also the perpendicular distance of the origin from this plane.

Equation of plane passing through (2,-3,1) and perpendicular to the join of (3,4,-1) and (2,-1,5) is

Equation of plane passing through (2,6,1) and perpendicular to the join of (-3,1,2) and (4,-3,6) is

Find the perpendicular distance of origin from of the plane 6x-2y+3z -7=0