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CD and GH are respectively the bisectors...

CD and GH are respectively the bisectors of `angleACB` and `angleEGF` such that D and H lie on sides AB and FE of `triangleABC` and `triangleEFG` respectively. If `triangleABC ~ triangleFEG`, show that :-`(CD)/(GH)=(AC)/(FG)` .

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