If AD and PM are medians of triangles ABC and PQR, respectively where `triangleABC~ trianglePQR` , Prove that `(AB)/(PQ)=(AD)/(PM)` .
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In Fig., ABC and AMP are two right triangles, right angled at B and M respectively. Prove that: (i) triangleABC ~ triangleAMP (ii) (CA)/(PA) = (BC)/(MP)

AD,BE and CF the altitudes of triangleABC are equal, prove that triangleABC is equilateral.

In Fig., ABC and AMP are two right triangles, right angled at B and M respectively. Prove that :- triangleABC~ triangleAMP . .

E and F are the mid points of non-parallel sides AD and BC respectively of a trapezium prove that EF||AB.

In the fig. AB=CD and AD=BC prove that triangleADCequivtriangleCBA

In the fig AB=CD and AD=BC. Prove that triangleADCequivtriangleCBA

Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR are median PN of trianglePQR . Show that triangleABCequivtrianglePQR

In the fig. AD is a median of triangle ABC and E is the mid point of AD, also BE meets AC in F. prove that AF=1/3AC

In Fig. , ABCD is a trapezium in which AB || DC and P, Q are mid-points of AD and BC respectively. If CP and BA when produced meet at E, prove that PQ=1/2(AB+DC) .

In Fig. , ABCD is a trapezium in which AB || DC and P, Q are mid-points of AD and BC respectively. If CP and BA when produced meet at E, prove that PQ=1/2(AB+DC) .