The area of a triangle is 5sq units. Two...

The area of a triangle is 5sq units. Two of its vertices are (2,1) and `(3, -2)`. The third vertex lies on `y=x+3`. The cordinates of the third vertex can be

A

`((-3)/(2), (-3)/(2))`

B

`((3)/(4), (-3)/(2))`

C

`((7)/(2), (13)/(2))`

D

`((-1)/(4),(1)/(2))`

Verified by Experts

The correct Answer is:

C

Similar Questions

Explore conceptually related problems

If area of triangle is 35 sq. units with vertices (2,-6), (5,4) and (k,4). Then k is_____

Find the area of a triangle whose vertices are (-4,1) , (5,-3) and (2,3) .

The area of the triangle whose vertices are A (1,-1,2), B (2, 1, -1) and C ( 3, -1, 2) is

Find the area of the triangle whose vertices are (3,8),(-4,2) and (5,1)

Find the area of a triangle with vertices A(2,3,1),B(1,1,2) and C(1,2,1).

Find the area of the triangle with vertices A(1,1,2),B(2,3,5) and C(1,5,5).

Area of the triangle with vertices ( - 2,2), (1,5) and (6, - 1 ) is

If 'A(2,-1)' B '(3,4), C(-2,3)' are the vertices of a parallelogram find the fourth vertex.

Find the area of the triangle with vertices at (-2,-3),(3,2),(-1,-8) using determinants.