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without actual division, find which of the following rational numbers have terminating decimal representation :
`(i)(3)/(64)" "(ii)(7)/(24)" "(iii)(17)/(400)" "(iv)(1)/(1250)" "(vi)(7)/(80)" "(iv)(21)/(500)`

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To determine which of the given rational numbers have a terminating decimal representation, we need to check if the denominator of each fraction, when expressed in its simplest form, can be written as \(2^m \times 5^n\), where \(m\) and \(n\) are non-negative integers. Let's analyze each case step by step. ### Step-by-Step Solution 1. **For \( \frac{3}{64} \)**: - The denominator \(64\) can be expressed as \(2^6\) (since \(64 = 2 \times 2 \times 2 \times 2 \times 2 \times 2\)). - Thus, \( \frac{3}{64} = \frac{3}{2^6 \times 5^0} \). - This is of the form \(2^m \times 5^n\) (where \(m=6\) and \(n=0\)). - **Conclusion**: This fraction has a terminating decimal representation. 2. **For \( \frac{7}{24} \)**: - The denominator \(24\) can be expressed as \(2^3 \times 3^1\) (since \(24 = 2 \times 2 \times 2 \times 3\)). - Thus, \( \frac{7}{24} = \frac{7}{2^3 \times 3^1} \). - The presence of \(3\) (which is not \(2\) or \(5\)) means it cannot be expressed in the required form. - **Conclusion**: This fraction does not have a terminating decimal representation. 3. **For \( \frac{17}{400} \)**: - The denominator \(400\) can be expressed as \(2^4 \times 5^2\) (since \(400 = 2 \times 2 \times 2 \times 2 \times 5 \times 5\)). - Thus, \( \frac{17}{400} = \frac{17}{2^4 \times 5^2} \). - This is of the form \(2^m \times 5^n\) (where \(m=4\) and \(n=2\)). - **Conclusion**: This fraction has a terminating decimal representation. 4. **For \( \frac{1}{1250} \)**: - The denominator \(1250\) can be expressed as \(2^1 \times 5^4\) (since \(1250 = 2 \times 5 \times 5 \times 5 \times 5\)). - Thus, \( \frac{1}{1250} = \frac{1}{2^1 \times 5^4} \). - This is of the form \(2^m \times 5^n\) (where \(m=1\) and \(n=4\)). - **Conclusion**: This fraction has a terminating decimal representation. 5. **For \( \frac{7}{80} \)**: - The denominator \(80\) can be expressed as \(2^4 \times 5^1\) (since \(80 = 2 \times 2 \times 2 \times 2 \times 5\)). - Thus, \( \frac{7}{80} = \frac{7}{2^4 \times 5^1} \). - This is of the form \(2^m \times 5^n\) (where \(m=4\) and \(n=1\)). - **Conclusion**: This fraction has a terminating decimal representation. 6. **For \( \frac{21}{500} \)**: - The denominator \(500\) can be expressed as \(2^2 \times 5^3\) (since \(500 = 2 \times 5 \times 5 \times 5\)). - Thus, \( \frac{21}{500} = \frac{21}{2^2 \times 5^3} \). - This is of the form \(2^m \times 5^n\) (where \(m=2\) and \(n=3\)). - **Conclusion**: This fraction has a terminating decimal representation. ### Summary of Results - **Terminating Decimal Representations**: - \( \frac{3}{64} \) - \( \frac{17}{400} \) - \( \frac{1}{1250} \) - \( \frac{7}{80} \) - \( \frac{21}{500} \) - **Non-Terminating Decimal Representation**: - \( \frac{7}{24} \)

To determine which of the given rational numbers have a terminating decimal representation, we need to check if the denominator of each fraction, when expressed in its simplest form, can be written as \(2^m \times 5^n\), where \(m\) and \(n\) are non-negative integers. Let's analyze each case step by step. ### Step-by-Step Solution 1. **For \( \frac{3}{64} \)**: - The denominator \(64\) can be expressed as \(2^6\) (since \(64 = 2 \times 2 \times 2 \times 2 \times 2 \times 2\)). - Thus, \( \frac{3}{64} = \frac{3}{2^6 \times 5^0} \). - This is of the form \(2^m \times 5^n\) (where \(m=6\) and \(n=0\)). ...
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