Evaluate :
`2.bar(5)-0.bar(35)`

Explanation

To evaluate the expression \(2.\overline{5} - 0.\overline{35}\), we will follow these steps:

### Step 1: Understand the repeating decimals
The notation \(2.\overline{5}\) means that the digit '5' repeats infinitely. Therefore, we can express it as:
\[ 2.\overline{5} = 2.55555\ldots \]
Similarly, \(0.\overline{35}\) means that the digits '35' repeat infinitely:
\[ 0.\overline{35} = 0.353535\ldots \]

### Step 2: Convert the repeating decimals to fractions
To make calculations easier, we can convert these repeating decimals into fractions.

**For \(2.\overline{5}\):**
Let \(x = 2.\overline{5}\). Then:
\[ x = 2.55555\ldots \]
Multiply both sides by 10:
\[ 10x = 25.55555\ldots \]
Now, subtract the first equation from the second:
\[ 10x - x = 25.55555\ldots - 2.55555\ldots \]
This simplifies to:
\[ 9x = 23 \]
Thus,
\[ x = \frac{23}{9} \]

**For \(0.\overline{35}\):**
Let \(y = 0.\overline{35}\). Then:
\[ y = 0.353535\ldots \]
Multiply both sides by 100:
\[ 100y = 35.353535\ldots \]
Now, subtract the first equation from the second:
\[ 100y - y = 35.353535\ldots - 0.353535\ldots \]
This simplifies to:
\[ 99y = 35 \]
Thus,
\[ y = \frac{35}{99} \]

### Step 3: Subtract the two fractions
Now we need to subtract the two fractions:
\[ 2.\overline{5} - 0.\overline{35} = \frac{23}{9} - \frac{35}{99} \]
To perform this subtraction, we need a common denominator. The least common multiple of 9 and 99 is 99. We convert \(\frac{23}{9}\) to have a denominator of 99:
\[ \frac{23}{9} = \frac{23 \times 11}{9 \times 11} = \frac{253}{99} \]
Now we can subtract:
\[ \frac{253}{99} - \frac{35}{99} = \frac{253 - 35}{99} = \frac{218}{99} \]

### Step 4: Simplify the result
The fraction \(\frac{218}{99}\) cannot be simplified further, so we can leave it as is.

### Final Result
Thus, the evaluation of \(2.\overline{5} - 0.\overline{35}\) is:
\[ \frac{218}{99} \]