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If sqrt(2)=1.414,sqrt(3)=1.732, find the...

If `sqrt(2)=1.414,sqrt(3)=1.732`, find the value of the following :
`(i)(sqrt(2)+1)/(sqrt(2)-1)" "(ii)(sqrt(3)-1)/(sqrt(3)+1)" "(iii)(2+sqrt(6))/(sqrt(2))`

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Let's solve the given problems step by step. ### Given: - \( \sqrt{2} = 1.414 \) - \( \sqrt{3} = 1.732 \) ### (i) Find the value of \( \frac{\sqrt{2} + 1}{\sqrt{2} - 1} \) **Step 1:** Multiply the numerator and denominator by \( \sqrt{2} + 1 \) to rationalize the denominator. \[ \frac{\sqrt{2} + 1}{\sqrt{2} - 1} \cdot \frac{\sqrt{2} + 1}{\sqrt{2} + 1} = \frac{(\sqrt{2} + 1)^2}{(\sqrt{2})^2 - (1)^2} \] **Step 2:** Simplify the denominator using the difference of squares formula. \[ = \frac{(\sqrt{2} + 1)^2}{2 - 1} = \frac{(\sqrt{2} + 1)^2}{1} \] **Step 3:** Expand the numerator. \[ (\sqrt{2} + 1)^2 = (\sqrt{2})^2 + 2 \cdot \sqrt{2} \cdot 1 + (1)^2 = 2 + 2\sqrt{2} + 1 = 3 + 2\sqrt{2} \] **Step 4:** Therefore, the expression simplifies to: \[ 3 + 2\sqrt{2} \] **Step 5:** Substitute \( \sqrt{2} \) with \( 1.414 \). \[ 3 + 2 \cdot 1.414 = 3 + 2.828 = 5.828 \] ### Answer for (i): \( 5.828 \) --- ### (ii) Find the value of \( \frac{\sqrt{3} - 1}{\sqrt{3} + 1} \) **Step 1:** Multiply the numerator and denominator by \( \sqrt{3} - 1 \). \[ \frac{\sqrt{3} - 1}{\sqrt{3} + 1} \cdot \frac{\sqrt{3} - 1}{\sqrt{3} - 1} = \frac{(\sqrt{3} - 1)^2}{(\sqrt{3})^2 - (1)^2} \] **Step 2:** Simplify the denominator. \[ = \frac{(\sqrt{3} - 1)^2}{3 - 1} = \frac{(\sqrt{3} - 1)^2}{2} \] **Step 3:** Expand the numerator. \[ (\sqrt{3} - 1)^2 = (\sqrt{3})^2 - 2 \cdot \sqrt{3} \cdot 1 + (1)^2 = 3 - 2\sqrt{3} + 1 = 4 - 2\sqrt{3} \] **Step 4:** Therefore, the expression simplifies to: \[ \frac{4 - 2\sqrt{3}}{2} = 2 - \sqrt{3} \] **Step 5:** Substitute \( \sqrt{3} \) with \( 1.732 \). \[ 2 - 1.732 = 0.268 \] ### Answer for (ii): \( 0.268 \) --- ### (iii) Find the value of \( \frac{2 + \sqrt{6}}{\sqrt{2}} \) **Step 1:** Multiply the numerator and denominator by \( \sqrt{2} \). \[ \frac{2 + \sqrt{6}}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}} = \frac{(2 + \sqrt{6})\sqrt{2}}{2} \] **Step 2:** Distribute \( \sqrt{2} \) in the numerator. \[ = \frac{2\sqrt{2} + \sqrt{6} \cdot \sqrt{2}}{2} = \frac{2\sqrt{2} + \sqrt{12}}{2} \] **Step 3:** Simplify \( \sqrt{12} \). \[ \sqrt{12} = \sqrt{4 \cdot 3} = 2\sqrt{3} \] **Step 4:** Substitute back into the expression. \[ = \frac{2\sqrt{2} + 2\sqrt{3}}{2} = \sqrt{2} + \sqrt{3} \] **Step 5:** Substitute \( \sqrt{2} \) and \( \sqrt{3} \) with their values. \[ = 1.414 + 1.732 = 3.146 \] ### Answer for (iii): \( 3.146 \) --- ### Summary of Answers: 1. (i) \( 5.828 \) 2. (ii) \( 0.268 \) 3. (iii) \( 3.146 \) ---

Let's solve the given problems step by step. ### Given: - \( \sqrt{2} = 1.414 \) - \( \sqrt{3} = 1.732 \) ### (i) Find the value of \( \frac{\sqrt{2} + 1}{\sqrt{2} - 1} \) ...
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NAGEEN PRAKASHAN ENGLISH-NUMBER SYSTEM-Exercise 1e
  1. Rationalise the denominator of each the following (i)(2)/(sqrt(3))" ...

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  2. Rationalise the denominator of each the of the following : (i)(1)/(3...

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  3. Simplify each of the following : (i)(sqrt(2)+1)/(sqrt(2)-1)+(sqrt(2)...

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  4. If sqrt(2)=1.414,sqrt(3)=1.732, find the value of the following : (i...

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  5. Find the value of a and b in each of the following (i)(3+sqrt(2))/(3...

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  6. If x=2+sqrt(3), then find : (i)(1)/(x)" "(ii)x+(1)/(x)" "(iii...

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  7. If x=3+2sqrt(2), then find : (i)(1)/(x)" "(ii)x+(1)/(x)" "(ii...

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  8. If x=(sqrt(3)+sqrt(2))/(sqrt(3)-sqrt(2)) and y=(sqrt(3)-sqrt(2))/(sqrt...

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  9. If a=1-sqrt(2),"then find the value of "(a-(1)/(a))^(3)

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  10. Evaluate 15/( sqrt10+sqrt20+sqrt40-sqrt5-sqrt80) is being given that s...

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  11. Write the following surds in descending order of their magnitudes : ...

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  12. If 25^(x-1)=5^(2x-1)-100, then find the value of x.

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  13. Which is greater sqrt(11)-sqrt(6) or sqrt(17)-sqrt(12) ?

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  14. If x=7-4sqrt3 then find the value of sqrtx+1/sqrtx

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  15. If x=2+sqrt(3), then find the value of x^(4)-4x^(3)+x^(2)+x+1.

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  16. Simplify sqrt(5+2sqrt(6))+sqrt(8-2sqrt(15))

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  17. If (9^n\ x\ 3^2\ x\ 3^n-\ 27^n)/(3^(3m)\ x\ 2^3)=1/(27) , prove that m...

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  18. Rationalise the denominator of : " "(2)/(sqrt(5)+sqrt(3)+2)

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