In Figure, `A B||C D`. Find the value of `x`

Explanation

Through FEG||AB||CD
Now, FE||AB and BE is the transversal
`:. angleABE+angleBEF=180^(@)` (co interior angles)
`rArr120^(@)+angleBEF=180^(@)`
`rArrangleBEF=60^(@)`

Agains as EG||CD and CE is tranvesersal
`angle DCE+angle GEC=180^(@)`
`rArr100^(@)+angle GEC=180^(@)`
`rArr angle GEC=80^(@)`
Now, `ngle DEF+ angle CEB+ angle GEC =180^(@)`
`rArr60^(@)+x+80^(@)=180^(@)" "` (` :.FEG` is a straight line)

`rArrx=40^(@)`
Hence,`x=40^(@)`