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In DeltaABC, bisectors of angleB and ang...

In `DeltaABC`, bisectors of `angleB and angleC` interesct each other at point O. Prove that `angleBOC=90^(@)+(1)/(2)angleA i.e., angle1 =90^(@)+(1)/(2)`A

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To prove that in triangle ABC, the angle BOC is equal to 90 degrees plus half of angle A, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Triangle**: We have triangle ABC with angle bisectors of angles B and C intersecting at point O. We need to prove that angle BOC = 90° + (1/2) angle A. 2. **Using the Angle Sum Property**: ...
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