Bisectors of angles A and D of a quadrilateral ABCD meet at P. Prove that `angleAPD=(1)/(2)(angleB+angleC)`

Bisectors of angles A and B of a parallelogram ABCD meet at point M. Prove that angleAMB=(1)/(2)(angleC+angleD)

If bisectors of angleA and angleB of a quadrilateral ABCD intersect each other at P, of angleB and angleC at Q, of angleC and angleD of R and of angleD and angleA at S, then PQRS is a (A) Rectangle (B) Rhombus (C) Parallelogram (D) Quadrilateral whose opposite angles are supplementary

In triangle ABC,the bisector of interior angle A and the bisector angle C meet at point O. Prove that angle AOC=(1)/(2)angleB

ABCD is a quadrilateral in which AB||DC and AD = BC. Prove that angleA=angleB and angleC= angleD .

In DeltaABC , bisectors of angleB and angleC interesct each other at point O. Prove that angleBOC=90^(@)+(1)/(2)angleA i.e., angle1 =90^(@)+(1)/(2)

In DeltaABC , bisectors of angleB and angleC interesct each other at point O. Prove that angleBOC=90^(@)+(1)/(2)angleA i.e., angle1 =90^(@)+(1)/(2) A

The bisectors of angleB and angleC of a quadrilateral ABCD intersect each other at point P. Show that P is equidistant from the opposite sides AB and CD.

In parallelogram ABCD, the bisectors of adjacent angles A and D intersect each other at point P. prove that angleAPD=90^(@) .

In a quadrilateral ABCD, AO and BO are bisector of angle A and angle B resepectively. Sho that : angleAOB=1/2 (angleC+angleD)

In a parallelogram ABCD, the bisectors of angleA and angleB intersect each other at point P. Prove that angleAPB=90^(@).