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In a rectangle ABCD, diagonals AC and BD...

In a rectangle ABCD, diagonals AC and BD intersect at O. If `angleOAB=35^(@),` find :
`(a)angleABC(b)angleABO(c)angleCOD (d)angle BOC)`

Text Solution

Verified by Experts

(a) `In angleABC,angleABC=90^(@)`
`" "thereforeangleACB=180^(@)-angleABC-angleCAB`
`180^(@)-90^(@)-35^(@)=55^(@)`

(b) `In DeltaABO, OA=OB`
`therefore" "angleABO=angleOAB=35^(@)`
( c) `" "angleCOD=angleAOB`
`=180^(@)-angleOAB-angleOBA`
`=180^(@)-35^(@)-35^(@)`
`=110^(@)`
(d) `angleBOC+angleCOD=180^(@)`
`therefore" "angleBOC=180^(@)-angleCOD = 180^(@)-110^(@)=70^(@)`
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