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In the given figure, ABCD is a square. F...

In the given figure, ABCD is a square. Find x.

Text Solution

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The diagonal BD of the squate ABCD bisects `angleABC`
`therefore" "anglePBE=1/2angleABC=1/2xx90^(@)=45^(@)`
Also `angleBPE`= opposite `angleDPC=75^(@)" "("vertically opposite angles")`
`In DeltaPEB "exterior"angleAEP=angleBPE+anglePBE" "("exterio angle theorem")`
`x=75^(@)+45^(@)=120^(@)`
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