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If the adjacent angles of a parallelogra...

If the adjacent angles of a parallelogram are in the ratio `1/3:1/2.` Find all the angles of parallelogram.

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To solve the problem of finding the angles of a parallelogram where the adjacent angles are in the ratio \( \frac{1}{3} : \frac{1}{2} \), we can follow these steps: ### Step 1: Define the Angles Let the adjacent angles of the parallelogram be represented as: - Angle A = \( \frac{1}{3}X \) - Angle B = \( \frac{1}{2}X \) Since opposite angles in a parallelogram are equal, we have: - Angle C = Angle A = \( \frac{1}{3}X \) - Angle D = Angle B = \( \frac{1}{2}X \) ### Step 2: Set Up the Equation The sum of all angles in a quadrilateral (including a parallelogram) is \( 360^\circ \). Therefore, we can write the equation: \[ \text{Angle A} + \text{Angle B} + \text{Angle C} + \text{Angle D} = 360^\circ \] Substituting the values we defined: \[ \frac{1}{3}X + \frac{1}{2}X + \frac{1}{3}X + \frac{1}{2}X = 360^\circ \] ### Step 3: Combine Like Terms Combining the terms on the left side: \[ \left(\frac{1}{3}X + \frac{1}{3}X\right) + \left(\frac{1}{2}X + \frac{1}{2}X\right) = 360^\circ \] This simplifies to: \[ \frac{2}{3}X + X = 360^\circ \] To combine the fractions: \[ \frac{2}{3}X + \frac{3}{3}X = \frac{5}{3}X \] Thus, we have: \[ \frac{5}{3}X = 360^\circ \] ### Step 4: Solve for X To find \( X \), multiply both sides by \( \frac{3}{5} \): \[ X = 360^\circ \times \frac{3}{5} = 216^\circ \] ### Step 5: Calculate the Angles Now we can find the measures of the angles: - Angle A = \( \frac{1}{3}X = \frac{1}{3} \times 216^\circ = 72^\circ \) - Angle B = \( \frac{1}{2}X = \frac{1}{2} \times 216^\circ = 108^\circ \) Since Angle C = Angle A and Angle D = Angle B, we have: - Angle C = \( 72^\circ \) - Angle D = \( 108^\circ \) ### Final Answer The angles of the parallelogram are: - Angle A = \( 72^\circ \) - Angle B = \( 108^\circ \) - Angle C = \( 72^\circ \) - Angle D = \( 108^\circ \)
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NAGEEN PRAKASHAN ENGLISH-QUADRILATERALS-Exercise 8a
  1. The give figure shows a square ABCD and an equilayeral teiangle APB. C...

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  2. In the given figure, ABCD is a rohombus with A=67^(@). If DEC is an eq...

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  3. If the adjacent angles of a parallelogram are in the ratio 1/3:1/2. Fi...

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  4. Prove that the sum of two consecutive angles of a parallelogram is 180...

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  5. One angle of a parallelogram is 60^(@). Find its remaining angles.

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  6. One diagonal of a parallelogram biscets its one of the angles. Show th...

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  7. The opposite angles of a parallelogram are (3x-2)^(@)and(150-x)^(@). F...

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  8. In the adjoining figure, ABCD is a parallelogram. If angleABC=125^(@),...

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  9. In a parallelogram, one angleis twice of its consecutiv angle. Find al...

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  10. In a parallelogram ABCD, AX and CY are the bisectors of angleAandangle...

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  11. In a parallelogram PQRS, PX and QY are the perpendiculars drawn from P...

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  12. In a parallelogram ABCD, the bisector of angleA bisects the line B at ...

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  13. In a parallelogram ABCD, angleBCD=60^(@) If the bisectors AP and BP of...

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  14. In the adjoining figure, DeltaPQR is formed by the sides PQ, QR and RP...

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  15. X and Y are the mid-points of the opposite sides AB and DC of a parall...

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  16. Two points X and Y lie on the diagonal BD of a parallelogram ABCD such...

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  17. In the adjoining figure, DeltaABC is an isosceles triangle in which AB...

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  18. AB and CD are two parallel lines and a transversal 'l' intersects thes...

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  19. In the adjoining figure squareABCD is a parallelogeam. Points X and Y ...

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  20. In the adjoining figure, ABCDEF is a regular hexagon. Prove that squar...

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