In the given figure, AM bisects angle A and DM bisects angle D of parallelogram ABCD. Prove that `angleAMD = 90^(@).`

In the figure, given below, AM bisects angle A and DM bisects angle D of parallelogram ABCD. Prove that: angleAMD= 90^(@)

In the figure , given below , CP bisects angle ACB. Show that DP bisect angle ADB .

In the given figure, AD = DB = DE angle EAC = angle FAC and angle F = 90 ^(@) Prove that (i) angle AEB = 90 ^(@) (ii) Delta CEG is isosceles. (iii) angle CEG = angle EAF

Find the angles of the parallelogram ABCD, if angle C = (2)/(3) angle D

In the given figure ABCD is a parallelogram. Prove that AB = 2BC.

Bisectors of angles A and B of a parallelogram ABCD meet at point M. Prove that angleAMB=(1)/(2)(angleC+angleD)

ABCD is a parallelogram E is mid-point of AB and DE bisects angle D. Prove that angleDEC= 90^(@)

Find the angles of the parallelogram ABCD, If angle A , angle B = 2: 7

In parallelogram ABCD, the bisectors of adjacent angles A and D intersect each other at point P. prove that angleAPD=90^(@) .

In the given figure, AB////EC,AB=AC and AE bisects angleDAC . Prove that: (i) angleEAC=angleACB (ii) ABCE is a parallelogram. .