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Bulbs are packed in cartons each containing 40 bulbs, seven hundred cartons were examined for defective bulbs and the results are given in the following table.

One carton was selected at random. What is the probability that it has
i) no defective bulb?
ii) defective bulbs from 2-6?
iii) defective bulbs less than 4?

Text Solution

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700 carton were examined for defective bulbs. One carton was selected at random.
(i) Let `E_(1)` be the event that selected carton has no defective bulb.
We see that the number of times the event happened = 400
`:." P"(E_(1))=("Number of trials in which the event happened")/("Total number of trials")=(400)/(700)=(4)/(7)`
(ii) Let `E_(2)` be the event that selected carton has defective bulbs from 2 to 6.
We see that the number of times the event happened
`=48+41+18+8+3=118`
`:." P"(E_(2))=("Number of trials in which the event happened")/("Total number of trials")=(118)/(700)=(59)/(350)`
(iii) Let `E_(3)` be the event that selected carton has defective bulbs less than 4.
We see that the number of times the event happened
`=400+180+48+41=669`
`:." P"(E_(3))=("Number of trials in which the event happened")/("Total number of trials")=(669)/(700)`
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