A dia is thrown 1000 times with the following frequencies for outcomes 1, 2, 3, 4, 5 and 6 as given below:
`|{:("Outcome",1,2,3,4,5,6),("Frequency",179,150,157,149,175,190):}|`
Find the probability of happening of each outcome.

Answer

To find the probability of each outcome when a die is thrown 1000 times, we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Frequencies**:
- Outcome 1: 179
- Outcome 2: 150
- Outcome 3: 157
- Outcome 4: 149
- Outcome 5: 175
- Outcome 6: 190

2. **Total Number of Throws**:
- The die was thrown a total of 1000 times.

3. **Calculate Probability for Each Outcome**:
The probability \( P \) of an outcome is calculated using the formula:
\[ P(\text{Outcome}) = \frac{\text{Frequency of Outcome}}{\text{Total Throws}} \]

- **Probability of Outcome 1**:
\[ P(1) = \frac{179}{1000} \]

- **Probability of Outcome 2**:
\[ P(2) = \frac{150}{1000} = \frac{15}{100} = \frac{3}{20} \]

- **Probability of Outcome 3**:
\[ P(3) = \frac{157}{1000} \]

- **Probability of Outcome 4**:
\[ P(4) = \frac{149}{1000} \]

- **Probability of Outcome 5**:
\[ P(5) = \frac{175}{1000} = \frac{17.5}{100} = \frac{7}{40} \]

- **Probability of Outcome 6**:
\[ P(6) = \frac{190}{1000} = \frac{19}{100} \]

4. **Summarize the Probabilities**:
- \( P(1) = \frac{179}{1000} \)
- \( P(2) = \frac{3}{20} \)
- \( P(3) = \frac{157}{1000} \)
- \( P(4) = \frac{149}{1000} \)
- \( P(5) = \frac{7}{40} \)
- \( P(6) = \frac{19}{100} \)