The following table shows the blood groups of 60 students of a class :
`|{:("Blood groups A B O AB"),("Number of students 16 12 23 9"):}|`
One student of the class is chosen at random. What is the probability that the chosen student has blood group?
`"(i) O (ii) AB (iii) A (iv) B"`

Answer

To solve the problem, we will calculate the probability of selecting a student with each specified blood group from the given data.

### Given Data:
- Total number of students = 60
- Number of students with blood group A = 16
- Number of students with blood group B = 12
- Number of students with blood group O = 23
- Number of students with blood group AB = 9

### Probability Formula:
The probability \( P \) of an event is given by the formula:
\[ P(\text{Event}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \]

### Step-by-Step Solution:

#### (i) Probability of having blood group O:
1. **Identify the number of favorable outcomes**: Number of students with blood group O = 23.
2. **Total outcomes**: Total number of students = 60.
3. **Calculate the probability**:
\[ P(O) = \frac{23}{60} \]

#### (ii) Probability of having blood group AB:
1. **Identify the number of favorable outcomes**: Number of students with blood group AB = 9.
2. **Total outcomes**: Total number of students = 60.
3. **Calculate the probability**:
\[ P(AB) = \frac{9}{60} = \frac{3}{20} \]

#### (iii) Probability of having blood group A:
1. **Identify the number of favorable outcomes**: Number of students with blood group A = 16.
2. **Total outcomes**: Total number of students = 60.
3. **Calculate the probability**:
\[ P(A) = \frac{16}{60} = \frac{4}{15} \]

#### (iv) Probability of having blood group B:
1. **Identify the number of favorable outcomes**: Number of students with blood group B = 12.
2. **Total outcomes**: Total number of students = 60.
3. **Calculate the probability**:
\[ P(B) = \frac{12}{60} = \frac{1}{5} \]

### Final Answers:
- (i) Probability of having blood group O = \( \frac{23}{60} \)
- (ii) Probability of having blood group AB = \( \frac{3}{20} \)
- (iii) Probability of having blood group A = \( \frac{4}{15} \)
- (iv) Probability of having blood group B = \( \frac{1}{5} \)