Two coins are tossed 1000 times and the outcomes are recorded as under :
`|{:("Number of heads"," 2 1 0"),("Frequency","266 540 194"):}|`
A coin is thrown at random. What is the probability of getting at most one head.

Answer

To solve the problem, we need to find the probability of getting at most one head when two coins are tossed 1000 times.

### Step-by-Step Solution:

1. **Understand the Outcomes**:
- When two coins are tossed, the possible outcomes for the number of heads can be:
- 2 heads
- 1 head
- 0 heads

2. **Record the Frequencies**:
- From the given data, we have:
- Frequency of 2 heads = 266
- Frequency of 1 head = 540
- Frequency of 0 heads = 194

3. **Define "At Most One Head"**:
- "At most one head" means we can have either 0 heads or 1 head. Therefore, we need to consider the frequencies for both of these outcomes.

4. **Calculate the Total Frequency for At Most One Head**:
- Total frequency for at most one head = Frequency of 0 heads + Frequency of 1 head
- Total frequency = 194 (for 0 heads) + 540 (for 1 head) = 734

5. **Calculate the Total Number of Tosses**:
- The total number of tosses is given as 1000.

6. **Calculate the Probability**:
- Probability of getting at most one head = (Total frequency for at most one head) / (Total number of tosses)
- Probability = 734 / 1000

7. **Simplify the Probability**:
- The fraction 734/1000 can be simplified if needed, but in decimal form, it is 0.734.

### Final Answer:
The probability of getting at most one head when two coins are tossed is \( \frac{734}{1000} \) or 0.734.

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