Home
Class 11
MATHS
Check whether the following relations ar...

Check whether the following relations are functions or not:
`R_(1)={(2,1),(5,1),(8,1),(11,1),(14,1),(17,1)}`
` R_(2)={(2,1),(4,2),(6,3),(8,4),(10,5),(12,6),(14,7)}`
`R_(3)={(1,3),(1,5),(2,5)}`

Text Solution

AI Generated Solution

The correct Answer is:
To determine whether the given relations are functions, we need to check if each input (first element of each ordered pair) is associated with exactly one output (second element of each ordered pair). ### Step-by-Step Solution: 1. **Check Relation R1:** - Relation: \( R_1 = \{(2,1), (5,1), (8,1), (11,1), (14,1), (17,1)\} \) - Inputs (first elements): 2, 5, 8, 11, 14, 17 - Outputs (second elements): 1, 1, 1, 1, 1, 1 - Each input (2, 5, 8, 11, 14, 17) is associated with the output 1. - Since every input has exactly one output, **R1 is a function**. 2. **Check Relation R2:** - Relation: \( R_2 = \{(2,1), (4,2), (6,3), (8,4), (10,5), (12,6), (14,7)\} \) - Inputs: 2, 4, 6, 8, 10, 12, 14 - Outputs: 1, 2, 3, 4, 5, 6, 7 - Each input is associated with a unique output. - Since every input has exactly one output, **R2 is a function**. 3. **Check Relation R3:** - Relation: \( R_3 = \{(1,3), (1,5), (2,5)\} \) - Inputs: 1, 1, 2 - Outputs: 3, 5, 5 - The input 1 is associated with two different outputs (3 and 5). - Since the input 1 has more than one output, **R3 is not a function**. ### Summary: - **R1 is a function.** - **R2 is a function.** - **R3 is not a function.**

To determine whether the given relations are functions, we need to check if each input (first element of each ordered pair) is associated with exactly one output (second element of each ordered pair). ### Step-by-Step Solution: 1. **Check Relation R1:** - Relation: \( R_1 = \{(2,1), (5,1), (8,1), (11,1), (14,1), (17,1)\} \) - Inputs (first elements): 2, 5, 8, 11, 14, 17 - Outputs (second elements): 1, 1, 1, 1, 1, 1 ...
Promotional Banner

Topper's Solved these Questions

  • RELATIONS AND FUNCTIONS

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 2A|20 Videos
  • RELATIONS AND FUNCTIONS

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 2B|14 Videos
  • PROBABILITY

    NAGEEN PRAKASHAN ENGLISH|Exercise MISCELLANEOUS EXERCISE|10 Videos
  • SEQUENCE AND SERIES

    NAGEEN PRAKASHAN ENGLISH|Exercise Miscellaneous Exercise|32 Videos

Similar Questions

Explore conceptually related problems

Examine each of the following relations given below and state in each case, giving reasons whether it is a function or not ? (i) R={(4,1),(5,1),(6,7)} (ii) R={(2,3),(2,5),(3,3),(6,6)} (iii) R={(1,2),(2,3),(3,4),(4,5),(5,6),(6,7)} (iv) R={(1,1),(2,1),(3,1),(4,1),(5,1)}

If A={1,2,3} and B={4,5,6} , then which of the following is a relation from set A to B? Give reason: (i) R_(1)={(1,5),(2,4),(3,5)} (ii) R_(2)={(4,1),(2,6),(5,1),(2,4)} (iii) R_(3)={(1,4),(2,5),(3,4),(2,6),(3,6)} (iv) AxxB

Which of the following relations are functions? Give reasons. If it is a function, determine its domain and range.(i) {(2, 1), (5, 1), (8, 1), (11 , 1), (14 , 1), (17 , 1)} (ii) {(2, 1), (4, 2), (6, 3), (8, 4),

Show that the following points are collinear : (i) (0,7,-7), (1,4,-5), (-1, 10,-9) (ii) (3,-5,1), (-1,0,8), (7,-10,-6) (iii) (-2,3,5),(7,0,-1),(1,2,3)

Which of the following is correct for data -1, 0, 1,2,3,5,5,6,8,10,11

Following relations from the set of natural number N to N are given: (a) R_(1)={(1,1),(4,2),(9,3),(16,4)} (b) R_(2)={(3,1),(4,2),(5,3),(6,4)} Represent them in set builder form.

Set builder form of the relation R={(-2, -7),(-1, -4),(0,-1),(1,2),(2,5)} is

Find the inverse of the following matrices if exist : (i) |{:(5,-3),(2,2):}| (ii) |{:(1,-3),(-1,2):}| (iii) |{:(1,0,-1),(3,4,5),(0,-6,-7):}| (iv) |{:(1,-3,3),(2,2,-4),(2,0,2):}| (v) |{:(1,2,1),(1,-1,-2),(1,2,-1):}| (vi) |{:(4,-2,-1),(1,1,-1),(-1,2,4):}|

Wherever possible write each of the following as a single matrix. (i) [{:(,1,2),(,3,4):}]+[{:(,-1,-2),(,1,-7):}] (ii) [{:(,2,3,4),(,5,6,7):}]-[{:(,0,2,3),(,6,-1,0):}] (iii) [{:(,0,1,2),(,4,6,7):}]+[{:(,3,4),(,6,8):}]

If A={1,2,3},B={3,4}and C={4,5,6}, "then prove that" (AxxB)uu(AxxC) ={(1,3),(1,4),(1,5),(1,6),(2,3),(2,4),(2,5 ),(2,6),(3,3),(3,4),(3,5),(3,6)}