By the principle of mathematical induction prove that `3^(2^(n))-1,` is divisible by `2^(n+2)`

Explanation

To prove that \(3^{2^n} - 1\) is divisible by \(2^{n+2}\) using the principle of mathematical induction, we will follow these steps:

### Step 1: Base Case
First, we check the base case for \(n = 1\).

\[ 3^{2^1} - 1 = 3^2 - 1 = 9 - 1 = 8 \]
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