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(1+i)^(4)+(1-i)^( 4) is equal to...

` (1+i)^(4)+(1-i)^( 4)` is equal to

A

8

B

-4

C

-8

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \( (1+i)^4 + (1-i)^4 \), we can follow these steps: ### Step 1: Rewrite the expression We start with the expression: \[ (1+i)^4 + (1-i)^4 \] ### Step 2: Use the property of exponents We can rewrite \( (1+i)^4 \) and \( (1-i)^4 \) as: \[ ((1+i)^2)^2 + ((1-i)^2)^2 \] ### Step 3: Calculate \( (1+i)^2 \) and \( (1-i)^2 \) Now, we calculate \( (1+i)^2 \) and \( (1-i)^2 \): \[ (1+i)^2 = 1^2 + 2 \cdot 1 \cdot i + i^2 = 1 + 2i - 1 = 2i \] \[ (1-i)^2 = 1^2 - 2 \cdot 1 \cdot i + i^2 = 1 - 2i - 1 = -2i \] ### Step 4: Substitute back into the expression Now substitute these results back into the expression: \[ (2i)^2 + (-2i)^2 \] ### Step 5: Calculate \( (2i)^2 \) and \( (-2i)^2 \) Calculating these squares gives: \[ (2i)^2 = 4i^2 = 4(-1) = -4 \] \[ (-2i)^2 = 4i^2 = 4(-1) = -4 \] ### Step 6: Combine the results Now we can combine these results: \[ -4 + (-4) = -8 \] ### Final Answer Thus, the value of the expression \( (1+i)^4 + (1-i)^4 \) is: \[ \boxed{-8} \]
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