`i^(-39)`

Text Solution

Verified by Experts

The correct Answer is:
N/a
`i^(-39)=i^(1-40)=(i)/(i^(40))i=0 +i*1`
Promotional Banner

Topper's Solved these Questions

  • COMPLEX NUMBERS AND QUADRATIC EQUATION

    NAGEEN PRAKASHAN ENGLISH|Exercise EXERCISE 5.2|8 Videos

  • COMPLEX NUMBERS AND QUADRATIC EQUATION

    NAGEEN PRAKASHAN ENGLISH|Exercise EXERCISE 5.3|10 Videos

  • COMPLEX NUMBERS AND QUADRATIC EQUATION

    NAGEEN PRAKASHAN ENGLISH|Exercise EXERCISE 5F|10 Videos

  • BINOMIAL THEOREM

    NAGEEN PRAKASHAN ENGLISH|Exercise Miscellaneous Exericse|20 Videos

  • CONIC SECTION

    NAGEEN PRAKASHAN ENGLISH|Exercise Miscellaneous Exercise|8 Videos

Similar Questions

Explore conceptually related problems

Simplify: 5/(26)+(11)/(-39)

Calculate the number of neutrons the following elements contain and state the formula used. (i) ""_(19)K^(39) " " (ii) ""_(9)F^(19) " " (iii)""_(4)Be^(9) " " (iv) ""_(13)Al^(27)

Simplify: (i) (-4/7) xx (21/20) , (ii) (-13)/9 xx (-21)/(-39)

The number of values of 'r' satisfying the equation ""^(39)C_(3r-1)- ""^(39)C_(r^(2) )= ""^(39)C_(r^(2)-1) - ""^(39)C_(3r) is

Find the points which divide the line segment joining A (1,-3) and B(-3,9) in the ratio 1 : 3 (i) internally and (ii) externally.

Divide: b. 13 div (39)/(40)

Find the sum of last 20 coefficients in the expansions of (1+x)^(39).

Calculate the number of proton, neutrons and electrons in ._(19)^(39) K .

Calculate the number of proton, neutrons and electrons in ._(19)^(39) K .

Find the value of (i) (i^(592)+i^(590)+i^(588)+i^(586)+i^(584))/(i^(582)+i^(580)+i^(578)+i^(576)+i^(574)) (i) -1 (ii) (1+i)^6+(1-i)^6