Convert of the complex number in the polar form: `3`

Answer

N/a

Explanation

Let -3 = `r(costheta +isintheta)`
`therefore" "rcos theta=-3 and rsintheta=0`
Now, `r^(2)cos^(2)theta+r^(2)sin^(2)theta=(- 3)^(2)+0=9`
`rArr" "r^(2)(cos^(2)theta+sin^(2)theta)=9`
`rArr" "r^(2)=9" "rArrr= 3`
Now, `{:("Now,",costheta=-1,,rArrtheta=pi),(and,sintheta=0 ,,rArr the ta= pior 2pi):}}rArr theta=pi`
Therefore, `-3=3(cospi+isinpi)`