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Solve the equation:x^2+3x+5=0...

Solve the equation:`x^2+3x+5=0`

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The correct Answer is:
N/a
Given equation is `x^(2)+ 3x+ 5=0`
Here, `a=1, b=3, c=5`
From Sridharacharya's formula
`" "x=(-bpmsqrt(b^(2)-4ac))/(2a)`
`" "x=(-3 pm sqrt(9- 4(1)(5)))/(2xx1)=(-3pmsqrt(- 11))/(2)`
`" "x=(-3pmisqrt11)/(2)`
Therefore, solutions of equation are
`" "x=(-3pmisqrt(11))/(2)`
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