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Solve the equation:x^2-x+2=0...

Solve the equation:`x^2-x+2=0`

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The correct Answer is:
N/a
Given equation is `x^(2)-x+ 2 =0`
Here, `a=1, b =-1, c=2`
Complex Numbers and Quadratic Equation
From Sridharacharya's formula
`" "x=(-bpmsqrt(b^(2) - 4ac))/(2a)`
`" "x=(1pmsqrt( (-1)^( 2)- 4(1)(2)))/(2(1))=( 1pmsqrt(-7))/(2)=(1pmisqrt(7))/(2)`
Therefore, solutions of the equation are
`" "x=(1pmsqrt (7))/(2)`
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