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Solve the equation: x^2+x/(sqrt(2))+1=0...

Solve the equation: `x^2+x/(sqrt(2))+1=0`

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The correct Answer is:
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Given equation is `x^(2)+(x)/(sqrt(2))+1=0`
`thereforeA=1, B=(1)/(sqrt(2)), C=1`
Discriminant `D=B^(2)=4AC=((1)/(sqrt(2)))^(2)-4xx1xx1`
`" "=(1)/(2)- 4 = -(7)/(2)`
Now, `" "x=(-Bpmsqrt(D))/(2A)=(-(1)/(sqrt(2))pmsqrt(-(7)/(2)))/(2*1)`
`" "=(-(1)/(sqrt(2))pmi( sqrt(7))/( sqrt(2)))/(2)`
`rArr" "x=(-1pmisqrt(7))/(2sqrt(2))`
`rArr" "x=(-1pmisqrt(7))/(2sqrt(2)) `
Therefore, solutions of equation are `x=(-1pmisqrt (7))/(2sqrt(2)) `
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