Solve the equation :`x^2-2x+3/2=0`

Answer

N/a

Explanation

Given equation is `x^(2)- 2x+(3)/(2)=0`
`rArr" "2x ^(2) -4x+3=0`
Here, `a=2, b=-4, c=3`
From Sridharacharya's formula,
`" "x= (-bpmsqrt(b ^(2)- 4ac))/(2a)`
`rArr" "x=(-(-4)pmsqrt((-4)^(2) -4(2)(3)))/(2xx2)`
`" "=(4pm sqrt(-8))/(4)=(4pm 2sqrt(2)i)/(4)=1pm (1)/(sqrt(2))i`