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If ((1+i)/(1-i))^m=1, then find the leas...

If `((1+i)/(1-i))^m=1,` then find the least positive integral value of `mdot`

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The correct Answer is:
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`(1 + i)/(1-i)=(1+ i)/(1- i)xx(1+ i)/(1+ i)`
` " "=(1+i^(2) +2i)/(1 -i^(2))=(1-1+2i)/(1+1)=i`
Now, ` ((1+i)/(1-i))^(m)=1`
`rArr" "i^(m)=1`
If `m` is positive, then
` " "m=4, 8, 12,...`
` therefore` Least positive value = 4
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NAGEEN PRAKASHAN ENGLISH-COMPLEX NUMBERS AND QUADRATIC EQUATION -MISCELLANEOUS EXERCISE
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