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If 1/(6!)+1/(7!)=x/(8!),find x...

If `1/(6!)+1/(7!)=x/(8!),`find x

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`(1)/(6!) + (1)/(7!) = (x)/(8!)`
`rArr x = 8! ((1)/(6!)+(1)/(7!))= (8!)/(6!) +(8!)/(7!)`
`=(8 xx 7 xx 6!)/(6!) +(8 xx 7!)/(7!)`
` = 56 +8 = 64`
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