If the different permutations of the word EXAMINATIION are listed as in a dictionary how many items are there in the listed before the first word starting with E?

Explanation

There will be `2I,2N,1A,1E,1X,1M, 1T,1O` in the words starting with A.
No. of words starting from `A = (10!)/(2!2!) = 907200`
After if, there will be words starting with `E, I,M, N,O,T,X`.
Therefore, the total no. of words before the words starting with E
`= 907200`