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Using binomial theorem, evaluate : (96)^...

Using binomial theorem, evaluate : `(96)^3`

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The correct Answer is:
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`96^(3)=(100-4)^(3)`
`=overset(3)underset(r=0)(Sigma).^(3)C_(r)=(100)^(3-r)(-4)^(r)`
`=^(3)C_(0).100^(3).(-4)^(@)+^(3)C_(1).100^(2).(-4)^(1)`
`+^(3)C_(2).100^(1).(-4)^(2)+^(3)C_(3).100^(@)(-4)^(3)`
`=1(1000000)+3.(10000)(-4)`
`+3.100(16)+1(-64)`
`=1000000-120000+4800-64`
`=884736`
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