There are 30 tickets numbered from 1 to 30. A ticket is drawn at random, find the probability of getting a ticket whose number is:
(i) multiple of 3
(ii) multiple of 7
(iii) multiple of 3 or 7

Answer

N/a

Explanation

No of possible outcomes of drawing a ticket `=.^(30)C_(1)=30`
(i) Multiple of 3 from 1 to 30 are 3,6,9,12,15,18,21,24,27,30.
No. of favourable ways of getting a multiple of `3=.^(10)C_(1)=10`
and probability of getting a multiple of `3=10/30=1/3`.
(ii) Multiple of 7 from 1 to 30 `=7,14,21,28`.
No. of favourable ways of getting a multiple of `7=.^(4)C_(1)=4`
and probability of getting a multiple of `7=4/30=2/15`.
(iii) Multiple of 3 or 7 from 1 to 30 `=3,6,7,9,12,14,15,18,21,24,27,28,30`.
No.of favourable ways of getting a multiple of 3 or
`7=.^(13)C_(1)=13`
and probability of getting a multiple of 3 or `7=13/30`