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Find the probability of getting the same number of two dice in a single throw of two dice.

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To find the probability of getting the same number on two dice in a single throw, we can follow these steps: ### Step 1: Determine the total outcomes when throwing two dice. When throwing two dice, each die has 6 faces (numbered from 1 to 6). Therefore, the total number of outcomes (denoted as \( n_s \)) when throwing two dice can be calculated as: \[ n_s = 6 \times 6 = 36 \] ### Step 2: Identify the favorable outcomes where both dice show the same number. The favorable outcomes (denoted as \( n_f \)) for the event where both dice show the same number are: - (1, 1) - (2, 2) - (3, 3) - (4, 4) - (5, 5) - (6, 6) Thus, the number of favorable outcomes is: \[ n_f = 6 \] ### Step 3: Calculate the probability. The probability \( P \) of both dice showing the same number is given by the ratio of the number of favorable outcomes to the total number of outcomes: \[ P = \frac{n_f}{n_s} = \frac{6}{36} = \frac{1}{6} \] ### Final Answer: The probability of getting the same number on two dice in a single throw is: \[ \frac{1}{6} \] ---

To find the probability of getting the same number on two dice in a single throw, we can follow these steps: ### Step 1: Determine the total outcomes when throwing two dice. When throwing two dice, each die has 6 faces (numbered from 1 to 6). Therefore, the total number of outcomes (denoted as \( n_s \)) when throwing two dice can be calculated as: \[ n_s = 6 \times 6 = 36 \] ...
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