There are 6 red and 4 white balls in a bag. Two-Two balls are drawn two times from this bag such that before drawing the balls second time the balls replaced in the bag which were drawing first time. Find the probability of getting 2 red balls in first time and 2 white in second time.

Answer

N/a

Explanation

Total balls `=6+4=10`
No. of ways of drawing 2 balls out of 10 balls `=.^(10)C_(2)=45`
No. of ways of drawing 2 red balls out of 6 red balls `=.^(6)C_(2)=15`
`:.` Probability of drawing 2 red balls in first time `=15/45=1/3`
Second time
No. of ways of drawing 2 balls out of 10 balls `=.^(10)C_(2)=45`
No. of ways of drawing 2 white balls out of 4 white balls `=.^(4)C_(2)=6`
`:.` Probability of drawing 2 white balls in second time `=6/45=2/15`
Now, the probability of drawing 2 red balls in first time and 2 white balls in second time
`=1/3xx2/15=2/45`