Two dice are thrown simultaneously find:
(i) Odds in favour of getting the sum of numbers
9 on two dice,
(ii) odds against of getting the sum of numbers 8 on two dice.

Answer

N/a

Explanation

In a throw of two dice
`n(S)=36`
(i) Let `E=` event of getting of 9 on two dice
`={(3,6),(4,5),(5,4),(6,3)}`
`= n(E)=4`
Now `P(E)=(n(E))/(n(S))=4/36=1/9`
`:.` Odds in favour event `E`
`=(P(E))/(1-P(E))=(1/9)/(1-1/9)=1/8-1:8`
(ii) Let `F=` event of getting a sum fo 8 on two dice
`={(2,6),(3,5),(4,4),(5,3),(6,2)}`
`implies n(F)=5`
Now `P(F)=(n(F))/(n(S))=5/36`
`:.` Odds againts of event `F=(1-P(F))/(P(F))=(1-5/36)/(5/36)`
`=31/5=21:5`