The probabilities of the occurrence of two events `E_(1)` and `E_(2)` are 0.25 and 0.50 respectively. The probability of their occurrence simultaneously is 0.15, find the probability that neither `E_(1)` nor `E_(2)` will occur.

Answer

N/a

Explanation

Here `P(E_(1)=0.25, P(E_(2))=0.50` and `P(E_(1)nnE_(2))=0.15`
Now `P(E_(1)uuE_(2))=(E_(1))+P(E_(2))-P(E_(1)nnE_(2))`
`=0.25+0.50-0.15`
`:. P` (neither `E_(1) `nor `E_(2)` )`=P(barE_(1)nnbarE_(2))`
`=Pbar((E_(1)uuE_(2))`
`=1-P(E_(1)uuE_(2))`
`=1-0.60`
`=0.40`