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A can hit a target 4 times out of 5 tria...

A can hit a target 4 times out of 5 trial. B can hit 3 times of 4 trials and C can hit 2 times out of 3 trials. If all three hit the target sumultaneously, find the probability of hitting the target.

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To solve the problem step by step, we will calculate the probability of at least one of A, B, or C hitting the target. ### Step 1: Determine the probabilities of success for A, B, and C. - **Probability of A hitting the target (P(A))**: A hits 4 times out of 5 trials. \[ P(A) = \frac{4}{5} \] - **Probability of B hitting the target (P(B))**: B hits 3 times out of 4 trials. \[ P(B) = \frac{3}{4} \] - **Probability of C hitting the target (P(C))**: C hits 2 times out of 3 trials. \[ P(C) = \frac{2}{3} \] ### Step 2: Calculate the probabilities of failure for A, B, and C. - **Probability of A missing the target (P(A'))**: A misses 1 time out of 5 trials. \[ P(A') = 1 - P(A) = 1 - \frac{4}{5} = \frac{1}{5} \] - **Probability of B missing the target (P(B'))**: B misses 1 time out of 4 trials. \[ P(B') = 1 - P(B) = 1 - \frac{3}{4} = \frac{1}{4} \] - **Probability of C missing the target (P(C'))**: C misses 1 time out of 3 trials. \[ P(C') = 1 - P(C) = 1 - \frac{2}{3} = \frac{1}{3} \] ### Step 3: Calculate the probability of all three missing the target. Since the events are independent (the success or failure of one does not affect the others), we can multiply the probabilities of failure: \[ P(A' \cap B' \cap C') = P(A') \times P(B') \times P(C') \] Substituting the values: \[ P(A' \cap B' \cap C') = \frac{1}{5} \times \frac{1}{4} \times \frac{1}{3} = \frac{1}{60} \] ### Step 4: Calculate the probability of at least one hitting the target. The probability of at least one hitting the target is given by: \[ P(\text{at least one hits}) = 1 - P(A' \cap B' \cap C') \] Substituting the value we found: \[ P(\text{at least one hits}) = 1 - \frac{1}{60} = \frac{60}{60} - \frac{1}{60} = \frac{59}{60} \] ### Final Answer: The probability of at least one of A, B, or C hitting the target is: \[ \frac{59}{60} \]

To solve the problem step by step, we will calculate the probability of at least one of A, B, or C hitting the target. ### Step 1: Determine the probabilities of success for A, B, and C. - **Probability of A hitting the target (P(A))**: A hits 4 times out of 5 trials. \[ P(A) = \frac{4}{5} ...
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NAGEEN PRAKASHAN ENGLISH-PROBABILITY-EXERCISE
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  2. The probability of happening of an event is 0.6 for one experiment. In...

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  3. A can hit a target 4 times out of 5 trial. B can hit 3 times of 4 tria...

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  4. ‘A’ can hit the target 3 times out of 5 times, ‘B’ can hit 2 times out...

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  5. The probability to pass in an examination of mathematics for three stu...

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  6. The probability of solving a problem by three students are 1/3,1/4,1/5...

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  7. There are 5 red and 7 white balls in one bag and 3 red and 8 white bal...

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  8. There are 5 red and 5 black balls in first bag and 6 red and 4 black b...

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  9. There are 4 white and 3 black balls in a bag. Find the probability of ...

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  10. There are 8 white and 7 black balls in a bag . Three balls are drawn t...

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  11. Two cards drawn without replacement from a well shuffled pack of 52 ca...

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  12. (i) There are 100 bulbs in a box, out of which 10 are defective. In a ...

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  13. In one toss of a coin, find the probability of getting: (i) head (ii...

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  14. In one toss of two coins together find the probability of getting: ...

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  15. In one toss of three coins together, find the probability of getting: ...

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  16. In one throw of a dice, find the probability of getting: (i) an even...

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  17. In one throw of two dice together, find the probability of getting: ...

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  18. In one throw of three dice together, find the probability of getting: ...

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  19. A card is drawn from a well shuffled pack of cards. Find the probabi...

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  20. There are two children in a family. Find the probability that at most ...

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