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The probability of solving a problem by three students are `1/3,1/4,1/5`. Find the probability that the problem will be solved if all three students try the problem simultaneously.

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To solve the problem, we need to find the probability that at least one of the three students solves the problem when they all try to solve it simultaneously. We can approach this using the concept of complementary probability. ### Step-by-Step Solution: 1. **Identify the probabilities of each student solving the problem:** - Let \( P(A) \) be the probability that student A solves the problem: \[ P(A) = \frac{1}{3} \] - Let \( P(B) \) be the probability that student B solves the problem: \[ P(B) = \frac{1}{4} \] - Let \( P(C) \) be the probability that student C solves the problem: \[ P(C) = \frac{1}{5} \] 2. **Calculate the probabilities of each student not solving the problem:** - The probability that student A does not solve the problem: \[ P(A') = 1 - P(A) = 1 - \frac{1}{3} = \frac{2}{3} \] - The probability that student B does not solve the problem: \[ P(B') = 1 - P(B) = 1 - \frac{1}{4} = \frac{3}{4} \] - The probability that student C does not solve the problem: \[ P(C') = 1 - P(C) = 1 - \frac{1}{5} = \frac{4}{5} \] 3. **Calculate the probability that none of the students solve the problem:** - Since the events are independent, the probability that none of the students solve the problem is: \[ P(A' \cap B' \cap C') = P(A') \times P(B') \times P(C') = \frac{2}{3} \times \frac{3}{4} \times \frac{4}{5} \] - Now, calculate this product: \[ P(A' \cap B' \cap C') = \frac{2 \times 3 \times 4}{3 \times 4 \times 5} = \frac{24}{60} = \frac{2}{5} \] 4. **Calculate the probability that at least one student solves the problem:** - The probability that at least one of the students solves the problem is the complement of the probability that none of them solve it: \[ P(A \cup B \cup C) = 1 - P(A' \cap B' \cap C') = 1 - \frac{2}{5} = \frac{3}{5} \] ### Final Answer: The probability that the problem will be solved if all three students try the problem simultaneously is: \[ \frac{3}{5} \]

To solve the problem, we need to find the probability that at least one of the three students solves the problem when they all try to solve it simultaneously. We can approach this using the concept of complementary probability. ### Step-by-Step Solution: 1. **Identify the probabilities of each student solving the problem:** - Let \( P(A) \) be the probability that student A solves the problem: \[ P(A) = \frac{1}{3} ...
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NAGEEN PRAKASHAN ENGLISH-PROBABILITY-EXERCISE
  1. ‘A’ can hit the target 3 times out of 5 times, ‘B’ can hit 2 times out...

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  2. The probability to pass in an examination of mathematics for three stu...

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  3. The probability of solving a problem by three students are 1/3,1/4,1/5...

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  4. There are 5 red and 7 white balls in one bag and 3 red and 8 white bal...

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  5. There are 5 red and 5 black balls in first bag and 6 red and 4 black b...

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  6. There are 4 white and 3 black balls in a bag. Find the probability of ...

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  7. There are 8 white and 7 black balls in a bag . Three balls are drawn t...

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  8. Two cards drawn without replacement from a well shuffled pack of 52 ca...

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  9. (i) There are 100 bulbs in a box, out of which 10 are defective. In a ...

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  10. In one toss of a coin, find the probability of getting: (i) head (ii...

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  11. In one toss of two coins together find the probability of getting: ...

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  12. In one toss of three coins together, find the probability of getting: ...

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  13. In one throw of a dice, find the probability of getting: (i) an even...

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  14. In one throw of two dice together, find the probability of getting: ...

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  15. In one throw of three dice together, find the probability of getting: ...

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  16. A card is drawn from a well shuffled pack of cards. Find the probabi...

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  17. There are two children in a family. Find the probability that at most ...

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  18. There are 7 red, 5 black and 3 white balls in a bag. A ball is drawn a...

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  19. There are 12 tickets numbered 1 to 12. A ticket is drawn at random. Fi...

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  20. The probability of the occurrence of an event is 3/8. Find the probabi...

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