In one throw of a dice, find the probability of getting:
(i) an even number
(ii) a multile of 3
(iii) a number greater than 4

Explanation

To solve the problem, we will calculate the probabilities for each of the specified events when throwing a dice.

### Step-by-Step Solution:

1. **Total Outcomes**:
When a dice is thrown, the total number of possible outcomes is 6. These outcomes are: {1, 2, 3, 4, 5, 6}.

2. **(i) Probability of getting an even number**:
- The even numbers on a dice are: {2, 4, 6}.
- Count of even numbers = 3.
- Probability of getting an even number (E) = Number of favorable outcomes / Total outcomes = 3 / 6 = 1 / 2.

3. **(ii) Probability of getting a multiple of 3**:
- The multiples of 3 on a dice are: {3, 6}.
- Count of multiples of 3 = 2.
- Probability of getting a multiple of 3 (M) = Number of favorable outcomes / Total outcomes = 2 / 6 = 1 / 3.

4. **(iii) Probability of getting a number greater than 4**:
- The numbers greater than 4 on a dice are: {5, 6}.
- Count of numbers greater than 4 = 2.
- Probability of getting a number greater than 4 (G) = Number of favorable outcomes / Total outcomes = 2 / 6 = 1 / 3.

### Final Answers:
- (i) Probability of getting an even number = 1/2
- (ii) Probability of getting a multiple of 3 = 1/3
- (iii) Probability of getting a number greater than 4 = 1/3