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The probability of non-occurrence of an ...

The probability of non-occurrence of an event is `5/12`. Find the probability of the occurrence of the event.

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To solve the problem, we need to find the probability of the occurrence of an event given that the probability of its non-occurrence is \( \frac{5}{12} \). ### Step-by-Step Solution: 1. **Understand the relationship between occurrence and non-occurrence**: The probability of occurrence of an event (let's denote it as \( P(A) \)) and the probability of non-occurrence of the event (denote it as \( P(A') \)) are related by the equation: \[ P(A) + P(A') = 1 \] This means that the sum of the probabilities of an event occurring and not occurring is always equal to 1. 2. **Identify the given probability**: We are given that the probability of non-occurrence of the event is: \[ P(A') = \frac{5}{12} \] 3. **Use the relationship to find the probability of occurrence**: We can substitute the value of \( P(A') \) into the equation from step 1: \[ P(A) + \frac{5}{12} = 1 \] 4. **Isolate \( P(A) \)**: To find \( P(A) \), we subtract \( \frac{5}{12} \) from 1: \[ P(A) = 1 - \frac{5}{12} \] 5. **Convert 1 into a fraction with a common denominator**: We can express 1 as \( \frac{12}{12} \): \[ P(A) = \frac{12}{12} - \frac{5}{12} \] 6. **Perform the subtraction**: Now we subtract the fractions: \[ P(A) = \frac{12 - 5}{12} = \frac{7}{12} \] 7. **Conclusion**: Therefore, the probability of the occurrence of the event is: \[ P(A) = \frac{7}{12} \] ### Final Answer: The probability of the occurrence of the event is \( \frac{7}{12} \).

To solve the problem, we need to find the probability of the occurrence of an event given that the probability of its non-occurrence is \( \frac{5}{12} \). ### Step-by-Step Solution: 1. **Understand the relationship between occurrence and non-occurrence**: The probability of occurrence of an event (let's denote it as \( P(A) \)) and the probability of non-occurrence of the event (denote it as \( P(A') \)) are related by the equation: \[ P(A) + P(A') = 1 ...
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NAGEEN PRAKASHAN ENGLISH-PROBABILITY-EXERCISE
  1. There are 12 tickets numbered 1 to 12. A ticket is drawn at random. Fi...

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  2. The probability of the occurrence of an event is 3/8. Find the probabi...

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  3. The probability of non-occurrence of an event is 5/12. Find the probab...

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  4. The odds in favour of an event are 3:4. Find the probability of the no...

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  5. The odds against of an event 5:3. Find the probability of the occurren...

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  6. There are 15 prizes and 25 blaks in a lottery. Find the probability of...

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  7. Two dice are thrown. Find the odds in favour of getting the sum 4.

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  8. Two letters are drawn from the english alphabets. Find the probabil...

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  9. A and B are two events such that P(A)=0.5, P(B)=0.4 and (A "or"B)=0.6,...

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  10. A and B are two events such that P(A)=0.60, P(A"or"B)=0.85 and P (A an...

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  11. (i) A and B are two events in a random experiment such that P(AuuB)=0....

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  12. For two mutually exclusive events A and B , P(A)=1/3 and P(B)=1/4, fi...

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  13. A, B, C are three mutually exclusive and exhaustive events associated ...

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  14. A number is selected at random from first 200 natural numbers. Find th...

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  15. A card is drawn at random from a well shuffled pack of 52 cards. Find ...

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  16. A card is drawn at random from a well shuffled pack of 52 cards. Find ...

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  17. Two cards are drawn at random from a well shuffled pack of 52 cards. F...

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  18. A pair of dice is thrown once. Find the probability of getting an even...

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  19. A dice is thrown twice. Find the probability of getting 3 at least one...

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  20. A card is drawn from a well shuffled pack of 52 cards. What is the pro...

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