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A card is drawn from a well shuffled pack of 52 cards. What is the probability that neither a spade nor a king will drawn?

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To find the probability that neither a spade nor a king will be drawn from a well-shuffled pack of 52 cards, we can follow these steps: ### Step 1: Determine the total number of cards The total number of cards in a standard deck is 52. ### Step 2: Count the number of spades In a deck of cards, there are 13 spades. ### Step 3: Count the number of kings There are 4 kings in a deck (one from each suit: hearts, diamonds, clubs, and spades). ### Step 4: Identify the overlap (spade that is also a king) Since one of the kings is also a spade, we need to account for this overlap. Therefore, there is 1 card that is both a spade and a king. ### Step 5: Calculate the probability of drawing a spade or a king Using the principle of inclusion-exclusion, the probability of drawing a spade or a king can be calculated as follows: \[ P(\text{Spade or King}) = P(\text{Spade}) + P(\text{King}) - P(\text{Spade and King}) \] Calculating each probability: - Probability of drawing a spade: \[ P(\text{Spade}) = \frac{13}{52} \] - Probability of drawing a king: \[ P(\text{King}) = \frac{4}{52} \] - Probability of drawing a card that is both a spade and a king: \[ P(\text{Spade and King}) = \frac{1}{52} \] Now substituting these values into the inclusion-exclusion formula: \[ P(\text{Spade or King}) = \frac{13}{52} + \frac{4}{52} - \frac{1}{52} = \frac{16}{52} \] ### Step 6: Simplify the probability of drawing a spade or a king \[ P(\text{Spade or King}) = \frac{16}{52} = \frac{4}{13} \] ### Step 7: Calculate the probability of drawing neither a spade nor a king The probability of drawing neither a spade nor a king is given by: \[ P(\text{Neither Spade nor King}) = 1 - P(\text{Spade or King}) \] Substituting the value we found: \[ P(\text{Neither Spade nor King}) = 1 - \frac{4}{13} = \frac{13 - 4}{13} = \frac{9}{13} \] ### Final Answer Thus, the probability that neither a spade nor a king will be drawn is: \[ \frac{9}{13} \] ---

To find the probability that neither a spade nor a king will be drawn from a well-shuffled pack of 52 cards, we can follow these steps: ### Step 1: Determine the total number of cards The total number of cards in a standard deck is 52. ### Step 2: Count the number of spades In a deck of cards, there are 13 spades. ...
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NAGEEN PRAKASHAN ENGLISH-PROBABILITY-EXERCISE
  1. There are 15 prizes and 25 blaks in a lottery. Find the probability of...

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  2. Two dice are thrown. Find the odds in favour of getting the sum 4.

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  3. Two letters are drawn from the english alphabets. Find the probabil...

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  4. A and B are two events such that P(A)=0.5, P(B)=0.4 and (A "or"B)=0.6,...

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  5. A and B are two events such that P(A)=0.60, P(A"or"B)=0.85 and P (A an...

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  6. (i) A and B are two events in a random experiment such that P(AuuB)=0....

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  7. For two mutually exclusive events A and B , P(A)=1/3 and P(B)=1/4, fi...

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  8. A, B, C are three mutually exclusive and exhaustive events associated ...

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  9. A number is selected at random from first 200 natural numbers. Find th...

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  10. A card is drawn at random from a well shuffled pack of 52 cards. Find ...

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  11. A card is drawn at random from a well shuffled pack of 52 cards. Find ...

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  12. Two cards are drawn at random from a well shuffled pack of 52 cards. F...

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  13. A pair of dice is thrown once. Find the probability of getting an even...

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  14. A dice is thrown twice. Find the probability of getting 3 at least one...

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  15. A card is drawn from a well shuffled pack of 52 cards. What is the pro...

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  16. The probability of the occurrence of event A is 1/3 and the probabilit...

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  17. There are 60% students in Maths and 30% in Biology. If 10% students ar...

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  18. There are 100 bolts and 50 nuts in a box, out of which 50% bolts and 5...

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  19. Two dice are thrown together. What is the probability that the sum ...

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  20. If A,B and C are three events, such that P(A)=0.3, P(B)=0.4, P(C)=0.8,...

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