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If A,B and C are three events, such that P(A)=0.3, P(B)=0.4, P(C)=0.8, P(AB)=0.08, P(AC)=0.28, P(ABC)=0.09. If `P(AcupBcupC)ge0.75`, then show that P(BC) kies in the interval `0.23lexle0.48`

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The correct Answer is:
`0.16`
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NAGEEN PRAKASHAN ENGLISH-PROBABILITY-EXERCISE
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